DateDiffDay (DbFunctions, Nullable<DateTime>, Nullable<DateTime>) Counts the number of day boundaries crossed between the. Currently I am only returning 1. Big right brace in enumerate environment Finding the wavefunction of coherent state in 2D oscillator Why does pattern not match?. DateDiff Syntax. You can use it in the same way as DATEDIFF function. use DATEDIFF(instead of DATEDIFE its a wrong keyword) There is a spelling mistake in your query. I found the challenge interesting and common enough and figured that my readers would probably find it interesting to work on as well. It accepts values from 1 to 38. DatePart. Try to use datediff with a less precise datepart. 2 Answers. The number of dateparts separating two date/time instances is too large. The datediff function resulted in an overflow. Para evitar problemas de ambigüedad, use años de cuatro dígitos. Confira Funções e tipos de dados de data e hora (Transact-SQL) para ter uma visão geral de todas as funções e tipos de dados de data e hora do Transact-SQL. The CONVERT function can convert datetime to string values. Finally, from the above examples, you can understand the process and uses of a DATEDIFF() function in SQL. Only return data type is bigint. CreationDate BETWEEN d. In this case, you need to specify DAY for DATETIME_ADD function. DATEDIFF_BIG menggunakan komponen offset zona waktu dari tanggal mulai atau berakhir untuk menghitung nilai yang dikembalikan. T-SQL DATEDIFF_BIG - 469ms diff with currentmills and documented start-end constraints incorrect? 2. Định nghĩa chính thức của Datediff SQL Server là tính sự khác biệt giữa. The application passes in two parameters: a string representing the number of the desired month (i. Here is an example: DECLARE @date1 DATETIME = GETUTCDATE () DECLARE @date2 DATETIME = DATEADD (DAY, -1, GETUTCDATE ()) DECLARE @zeroDate DATETIME = 0 SELECT DATEADD (SECOND, DATEDIFF (SECOND, @date1, @date2), @zeroDate) I also set up an SQLFiddle where you can try that out. 2. The first value in the interval. With the birth of SQL Server 2016, Microsoft has introduced a new DATEDIFF SQL function, an enhanced version of DATEDIFF known as DATEDIFF_BIG. Parentheses are optional when called with no arguments. For a smalldatetime value used for startdate or enddate , DATEDIFF_BIG always sets seconds and milliseconds to 0 in the return value because smalldatetime only has accuracy to the minute. We can find the difference between the two dates using the following dateparts with the DATEDIFF function. Use DATEDIFF_BIG function if you are using SQL Server 2016+. 27' which means 270ms rather than 27ms. However,in your sitution ,you use DATEDIFF() as the number of DATEADD (datepart ,number, date ). Start Date = 08/25/2006 , End Date = 06/22/2020 , "Y". The SQL DATEDIFF_BIG function is supported for the following types: Instant (extension methods) OffsetDateTime (extension methods) LocalDateTime (extension methods) LocalTime (extension methods) Duration (extension methods) Note: Please add a using statement in order to use the extension methods: using Microsoft. We can add or subtract a numeric value to a specified date-time to get future or past timelines. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. The file is located under App_Code folder. Find the interval between today's date and a column. However,in your sitution ,you use DATEDIFF() as the number of DATEADD (datepart ,number, date ). It returns the bigint difference between the startdate and enddate, expressed in the boundary set by datepart. Resolved issues. Specifically, it gets the difference between 2. The SQL DATEDIFF_BIG function is supported for the following types: ; Instant (extension methods) ; OffsetDateTime (extension methods) ; LocalDateTime (extension methods) ; LocalTime (extension methods) ; Duration (extension methods) . DATEDIFF trong SQL Server là một hàm cơ bản được dùng để triển khai các phép tính dựa trên ngày tháng. SqlServer. Usage Notes¶. Fortunately, if you really must find out how many nanoseconds are in 100 years, you can use the DATEDIFF_BIG() function instead. Push out all due dates by one week. New date objects in SQL Server 2016 – DATEDIFF_BIG and AT TIME ZONE; SQL date format Overview; DateDiff SQL function, DateAdd SQL function and more; DATEPART. From documentation: If the repository is using Oracle or DB2, the return value is a floating point number. 1 microseconds? According to stackoverflow user CodesInChaos “ticks are simply the smallest power-of-ten that doesn’t cause an Int64 to overflow when. Shared":{"items":[{"name":"ConverterAttributes","path":"Project/LambdicSql. Maybe not. txt","path":"inst/csv/jarChecksum. Adds a specified time interval to a DATETIME value. For example, adding three months or 12 days to a starting date. The SQL DATEDIFF_BIG function is supported for the following types: Instant (extension methods) OffsetDateTime (extension methods) LocalDateTime (extension methods) LocalTime (extension methods) Duration (extension methods) Note: Please add a using statement in order to use the extension methods:Adding n seconds to 1970-01-01 will give you a UTC date because n – the Unix timestamp – is the number of seconds that have elapsed since 00:00:00 Coordinated Universal Time (UTC), Thursday, 1 January 1970. Is there any other way to get result. This function supports the following arguments: time_zone_expression: A STRING. 0000000') GO The datediff function resulted in an overflow. DATEDIFF SQL Server Function; SQL Date Function Tutorial - DATEADD, DATEDIFF, DATENAME, DATEPART and more; Getting Started with SQL DATEDIFF and DATEDIFF_BIG Functions. units – A unit of measure for describe the difference between the dates. PostgreSQL - Date Difference in Weeks. ; Background. Database engine runs the translated T-SQL and returns the query result ideally. So to get around that, there's also a DATEDIFF_BIG() function that does the same thing but returns a bigint instead. To calculate the number of days between date1 and date2, you can use either. andy andy. Use DATEDIFF_BIG function if you are using SQL Server 2016+. Try to use datediff with a less precise datepart. The number of dateparts separating two date/time instances is too large. month ( [bd]) > month (getdate ())Support for the following functions: STR, APP_NAME, OBJECT_DEFINITION, OBJECT_SCHEMA_NAME, ATN2, DATEDIFF_BIG functions. End Date: The date you want to count the difference to. DATEPART ( date_part ,. 0000000', '2016-1-1 00:00:00. The datediff function resulted in an overflow. Plus one for the example that shows GETDATE () and not just DATEDIFF, which is part of what OP needs. In SQL Server: Like we do in SQL Server its much easier. Hi All, I have a long string like below in my column and I am getting date from that. You would ideally use the DATEDIFF_BIG () function which returns a bigint that allows for values up to 9,223,372,036,854,775,807 or ~9 Septillion. The datediff function resulted in an overflow. COMB Purpose. The return datatype of INT and the maximum it can have the value 2147483647. Today : CONVERT(date, GETDATE()) : DateTime. CLOSEDDATE, '1776-07-04') = '1776-07-04' OR DATEDIFF (MI, OPENDATE, A. If we need to generate a report for a quarter then we need to include all the transactions happening on the last date of the quarter till mid night. There is a limit to how big the difference can be. The best will likely be: SELECT <column list> -- not * (1) FROM dbo. targetColumn – A name for the newly created column. In “Table Tools” tab, click on “ New Column ” to create a new Column using DAX. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. DATEFROMPARTS returns the date from the dateparts. Example # This example returns a date from the year, month, and day dateparts. NET SQL Added in : DateTime. The resulting datatype for DATEDIFF is INT and the resulting datatype for DATEDIFF_BIG is BIGINT. DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. Become an expert!: Enterprise DNA. Transact-SQL syntax conventions. However, we can easily simulate it by taking a difference of days, using the DAYS () function: SELECT DAYS (DeliveryDate) - DAYS (ReceiptDate) AS days_diff FROM ORDERS; Share. Description Returns the current date as a DATE object. TotalAgility documentation. DATE_FORMAT () – Displays date/time data in. For example; 8 - (-4) = 8 + 4. The DATEADD function, on the other hand, doesn’t need to round anything. currentTimeMilliseconds () RETURNS BIGINT WITH EXECUTE AS CALLER AS BEGIN DECLARE @t datetime = CONVERT (datetime, GETUTCDATE ()); DECLARE. Release NotesFirst, the logic: 1: Do a straightforward DateDiff for Years. The example above shows the result of DATE_DIFF for two days in succession. Actually, the marked answer originally produced wrong results for milliseconds 1 - 99: Example 1 second, 27 milliseconds: DATEDIFF % 1000 will return 27. DATEDIFF() measures the number of time boundaries between two date/time values. Discover how to retrieve the current date and time, filter records between specific dates or timestamps, extract parts of a timestamp, find the day of the week, and convert timestamps to Unix timestamps for easier comparison and calculation. Ask Question Asked 6 years, 5 months ago. Learn more about Teams2. The number of dateparts separating two date/time instances is too large. We will use the below date for the examples. RANK. In Power BI Desktop, Click on Data Mode. CREATE FUNCTION UNIX_TIMESTAMP() RETURNS BIGINT AS BEGIN RETURN DATEDIFF_BIG(millisecond, '1970-01-01 00:00:00', GETUTCDATE()) END And execute it The datediff function resulted in an overflow. Added support to generate data definition scripts for various objects present in. You can use our tools as a set or as a great example of how to write functions like these. The DATEDIFF_BIG function is used in the same way as the DATEDIFF function. Learn how to query and manipulate date and time data in SQL Server using datetime and timestamp values. DateDiff_Big is only available since SQL Server 2016. It returns the bigint difference between the startdate and enddate, expressed in the boundary set by datepart. However, if the time crosses midnight then you'll get a large negative value of DATEDIFF. so, the secondValueA changes everytime the time changes. Valid values are MONTHS, YEARS , MILLISECONDS, QUARTERS, HOURS , MICROSECONDS, WEEKS, SECONDS , DAYS, and MINUTES. SELECT YEAR(OrderDate) AS Year, SUM(TotalAmount) AS 'Annual Sales' FROM [Order] GROUP BY ROLLUP(YEAR(OrderDate)) Try it live. The datediff function resulted in an overflow. The DATEDIFF is the normal function in the T-SQL that can be used to perform mathematical calculations depending on the dates; it provides the output as integer values as dates, months, years, minutes, and seconds. COMB Purpose. SELECT DATEDIFF(YEAR,'2008-06-05','2010-06-05') AS XXX Share. DATEDIFF returns an INT so it cannot be used to return difference in millisecond if the two dates are far (approx. The function will always return the difference between two dates in days. In older versions there is a limit on the return value of DATEDIFF function. In SQL SERVER, you can use the following query (replace the date with your field): SELECT CASE WHEN datediff (year, '20120303', getdate ()) > 1 THEN datediff (year, '20120303', getdate ()) ELSE datediff (day, '20120303', getdate ()) END AS Diff. 25 days) apart. The style argument is mostly used to display the datetime in a specific format. In my previous GDPR tip, I discussed deleting someone’s information to comply with a “forget me” request, and how you must ensure the data is really gone. This example uses different types of expressions as arguments for the startdate and enddate parameters. , year-over-year) and cumulative (e. . Usage. SELECT MSTR. Konvensi sintaks transact-SQL. The syntax for DATEDIFF and DATEDIFF_BIG are both similar however DATEDIFF will return a int value and the DATEDIFF_BIG will return a big Read More SQL Server String Split function available in SQL Server 2016. Transact-SQL syntax conventions. 5,999 2 2 gold badges 27 27 silver badges 49 49 bronze badges. Luckily, there’s a handy DATEDIFF function that can do that for you. DAY() Returns the day of the month as an integer between 1 and 31. This was negatively affecting their. The number of dateparts separating two date/time instances is too large. 1 Answer. Data Collaboration Overview. See DATEDIFF_BIG (Transact-SQL) for a function that handles larger differences between the startdate and enddate values. So the difference between these two functions is. The following functions can be used to return the difference between two different date/time values. Here is a Microsoft SQL function that returns UTC time in milliseconds (Milliseconds since 1970) its result is equal to Java. In C# i wrote like this select car_id,cust_id,due,DATEDIFF(GETDATE(),due) as elap from rental where. DATEDIFF_BIG resta startdate de enddate. And for the number type in 'DATEADD ',it must be INT. 11. bigint: Deterministic But upon execution, I get the following error: The datediff function resulted in an overflow. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. STDEV (DATEDIFF (MINUTE, CAST ('00:00' AS time), YourTimeColumn)) That, of course, will give you the deviation in minutes. Share. SQL DateDiff_Big . 语法 DATEDIFF ( datepart , startdate , enddate )Mar 27, 2013 at 14:06. (Integer division will produce an integer result. DATEDIFF_BIG resta startdate de enddate. SELECT datediff (F. Reply. Leave a Reply Cancel reply. Use DATEDIFF_BIG function if you are using SQL Server 2016+. First, here’s the syntax: DATEDIFF_BIG ( datepart , startdate , enddate ) Where datepart is the part of the date that you want compared. Follow answered Apr 14, 2021 at 1:53. The syntax for DATEDIFF DAX function is: = DATEDIFF (Start Date, End Date, Interval) Start Date: The date you want to count the difference from. NodaTime. However, the DATEDIFF_BIG function is typically. . Below query confirms that a negative date is similar to a negative integer. Esta función devuelve el recuento (como un valor entero con firma) de los límites datepart que se han cruzado entre los valores startdate y enddate especificados. DAY(), MONTH() and YEAR() are internally interpreted as their DATEPART() counterparts, which can be seen in the execution plan properties as well. Use DATEDIFF_BIG function if you are using SQL Server 2016+. Dividing that by 1000000000 gives us 2147483648, which is +1 larger than the maximum value for an INT. Both integer (int) and big integer (bigint) are numeric data types used to store integer values. SQL SERVER – Learning DATEDIFF_BIG Function in SQL Server 2016. DATEDIFF_BIG(millisecond, '1970-01-01T00:00:00. Returns integer representation of the first character of the expression. Improve this answer. Perhaps you can point a separate cell at the range and create a single value from it, and then DateDiff that? Or use a variable that does it, like:. Untuk nilai smalldatetime yang digunakan untuk startdate atau enddate , DATEDIFF_BIG selalu atur detik dan milidetik ke 0 dalam nilai yang dikembalikan karena smalldatetime hanya memiliki akurasi hingga menit. CAST(EXTRACT(epoch FROM NOW()) AS BIGINT) expression is wrong. 1. FromDate, r. It works the same as DATEDIFF() with the exception that it returns the result as a signed bigint (as opposed to an int for DATEDIFF()). It's worth your while becoming proficient in SQL. DateDiffDay (DbFunctions, Nullable<DateTime>, Nullable<DateTime>) Counts the number of day boundaries crossed between the startDate and endDate . But, sometimes this may result in overflow. . Syntax DATE_DIFF (date_expression_a,. Posts AS p WHERE EXISTS ( SELECT 1/0 FROM #d AS d WHERE p. I am trying to fetch the records from the SQL server between 2 Unix timestamps (milliseconds) by converting the DateTime column LastUpadted to milliseconds. date_part is the part of date e. Syntax for DATEDIFF function is DATEDIFF(date_part, date1, date2) Result value depends on DB under your repository. Try to use datediff with a less precise datepart. SELECT DATEDIFF_BIG ( millisecond, SYSDATETIME (), DATEADD (year, 1000, SYSDATETIME ()) ) AS 'Milliseconds in 1000 years'; Share. The DATEDIFF_BIG() function returns a 64-bit bigint data type, that can store values up to 9,223,372,036,854,775,807. Basically, you are just obtaining the difference, in the given units, between the timestamp of 00:00:00. VB. The datediff function resulted in an overflow. 0000000' AS TIME),@T),@D) The datediff function resulted in an overflow. Adds native support to EntityFrameworkCore for SQL Server for the NodaTime types. It could be too big for an integer. It determines the difference between 2 dates, for example, 2/5/2016 minus 2/1/2016 = 4 days. maybe this answer will help someone. You shouldn't be converting to time - it is meant to store a point in time on a single 24h clock, not a duration or interval (even one that is constrained on its own to < 24 hours, which clearly your data is not). Time for the big guns. To understand the. You get the difference in days. Sorted by: 1. An integer only allows values up to 2,147,483,647. Enclose string constant dates in quotation marks. Covering popular subjects like HTML, CSS, JavaScript,. SqlServer. Calculates the difference between two date, time, or timestamp expressions based on the date or time part requested. ) and the. . When epoch is extracted from that it gives you Unix timestamp in your DB's (or client) time zone, not in UTC! Seems like we must configure our database to work in UTC too!In the following example, different parts of two intervals are extracted. Disable null values in a table. 9999999', '2023-10-02 00:00:00. If you go down to the SECOND date part, the query's maximum time difference is 68 years, 19 days, 3 hours, 14 minutes and 7 seconds. It returns the bigint difference between the startdate and enddate, expressed in the boundary set by datepart. It uses datetime2 (7) data type output value. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. I have a database in which I have a table with a 'datetime' field. Example 4. Expand user menu Open settings menu. Currently, my code just returns zero on the right side of the decimal place. DATEDIFF() uses the time zone offset component of the startdate or enddate to calculate the return value. A student of mine sent me a T-SQL challenge involving gap-filling of missing dates and balances. Recently we found out that one of the third party application for the client is not closing the connections which they open after completing the transactions. Function list. Reply MaunaLoona • Additional comment actions. stop is specified as a variable, a literal, or a scalar expression of type tinyint, smallint, int, bigint, decimal, or numeric. A . that new years start). DATE_DIFF with the date part WEEK returns 1 because DATE_DIFF counts the number of date part boundaries in this range of dates. See DATEDIFF_BIG (Transact-SQL) for a function that handles larger differences between the startdate and enddate values. Syntax of the DATEADD function . In other words, properly stated, on 2/1/2016 it is 4 days until 2/5/2016, and on 2/5/2016, 2/1/2016 was 4 days ago. Only return data type is. 2. 0000000+00:00', @dateTimeOffset) EF Core 8. And for the number type in 'DATEADD ',it must be INT. Fortunately, if you really must find out how many nanoseconds are in 100 years, you can use the DATEDIFF_BIG function instead. DateGroup. See DATEDIFF_BIG (Transact-SQL) for a function that handles larger differences between the startdate and enddate values. Copyright (c) 2017, Mark Adams ([email protected] datepart passed to DATEDIFF will control the resolution of the output. If you have an earlier version, you can do something similar with DateDiff, but it's slightly more. The DATEDIFF_BIG () function works exactly the same way, but with one subtle difference: Its return data type. Add a comment. 000', LastUpadted AT TIME ZONE 'UTC') BETWEEN 1620459590247 AND. , a year, a quarter, a month, a week that you want to compare between the start_date and end_date . Para date, DATEDIFF_BIG aceptará una expresión de columna, una expresión, un literal de cadena o una variable definida por el usuario. TIMESTAMPDIFF () Subtract an interval from a datetime expression. Version information. Follow. For clarity, I would explicitly convert to character strings:The Curity Identity Server provides a username/password (HTML Form) authenticator out-of-the-box that can lock a user based on a configured number of failed authentication attempts. Two dates to calculate the number of days between. The DATEDIFF() function returns the number of days between two date values. To track the shipping turnaround time, we can use the DATEDIFF () function. Syntax DATEDIFF ( datepart , startdate ,. We can add or subtract a numeric value to a specified date-time to get future or past timelines. Add a comment | Your Answer. {"payload":{"allShortcutsEnabled":false,"fileTree":{"Project/LambdicSql. Para evitar problemas de ambigüedad, use años de cuatro dígitos. Modified 6 years, 5 months ago. Precision includes both left and right side of decimal point. However you could calculate the difference in seconds, BIGINT multiply by 1000, and add the milliseconds: SELECT DATEDIFF (SECOND, '1970-01-01', dateCompleted) * CAST (1000 AS BIGINT) + DATEPART (MILLISECOND. You need a two-step approach with select DATEADD(SECOND, 2551564800 % 3600, DATEADD(HOUR, 2551564800 / 3600, '19700101')). 0 is for 1/1/1900, and getdate is the current date --(i used a set date bc dates will change as this post gets older). Remarks. 3. The number of dateparts separating two date/time instances is too large. Sum (r => EF. SELECT server_instance_name,event_time, session_id, database_name, client_ip, server_principal_name, application_name, statement, succeeded, DATEDIFF_BIG(ns, ‘1970. TotalAgility 7. I have a separate program that writes in this row the current timedate like '2018-10-05 09:58:30. It can be used to do date math as well. The following example adds various values (one year, one month, one day, one hour) to the date July 3, 2020 at midnight (00:00 UTC). The number of dateparts separating two date/time instances is too large. To understand. The number of dateparts separating two date/time instances is too large. (also screen shot 3). So the difference between these two functions is the data type of their return value. Optionally, the date format can be specified with a style argument (see below for options). In SQL Server: Like we do in SQL Server its much easier. The decimal value comes in handy later. ROW_NUMBER. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. But, sometimes this may result in overflow. Example. currentTimeMillis () CREATE FUNCTION dbo. Formats a TIME value according to the specified format string. Net tick is a duration of time lasting 0. Result: '1. When GUIDs (uniqueidentifier values in MSSQL parlance, UUID in PostgreSQL) are part of a database index, and particularly when they are part of the clustered index, the. Instead, use the dateAdd function on todays date, and compare the database table column to the result of that single calculation. See Date and Time Data Types. dk's, because DateDiff returns an Int, which means it tops out at ~24 days worth of milliseconds and ~67 yrs. Date Function DATEDIFF_BIG. It can be SECOND, MINUTE, HOUR, DAY, WEEK, MONTH, QUARTER, YEAR. 795. [AREA],T. [date2timestamp] (@Date datetime2(7)) RETURNS bigint AS BEGIN RETURN DATEDIFF_BIG(MICROSECOND, '19700101', @Date); END; maybe this answer will help someone. 2: Add Years to the start date, so you can then get the remaining months. The DATEDIFF function will return the difference count between two DateTime periods with an integer value whereas the DATEDIFF_BIG function will return its output in a big integer value. Try to use datediff with a less precise. One of the T-SQL functions introduced in SQL Server 2016 is DATEDIFF_BIG function. Application. This ensures the correct database context. Try to use datediff with a less precise datepart. And for the number type in 'DATEADD ',it must be INT. The only functional difference between them is that the DATEDIFF_BIG() returns values as a BIGINT, for results that exceed the boundary of an INT. dto ); Which results in a rather sad-looking execution plan: Nested Loops is the only join operator available, since we don't have an equality predicate. txt","contentType":"file"},{"name. g. When GUIDs (uniqueidentifier values in MSSQL parlance, UUID in PostgreSQL) are part of a database index, and particularly when they are part of the clustered index, the. . – Nitin Deb. 0. DATEDIFF in the where clause will be evaluated for all the records in the table and will overflow on the LastCheckIn with value 1900-01-01 00:00:00. AS 'Quarter Start Date', DATEADD (d, -1, DATEADD (q, DATEDIFF (q, 0, @AnyDate) + 1, 0)) AS 'Quarter End Date'. This function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified startdate and enddate. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. e. SQL DATEPART. 8. Functions. Date Function DATEDIFF_BIG. NET Core library does two things: generates "COMB" Guid values in C#; and, extracts the DateTime value from an existing COMB Guid. You can use DATEDIFF (), there is no equivalent of INTERVAL in SQL Server. For a smalldatetime value used for startdate or enddate , DATEDIFF_BIG always sets seconds and milliseconds to 0 in the return value because smalldatetime only has accuracy to the minute. 1 microseconds? According to stackoverflow user CodesInChaos “ticks are simply the smallest power-of-ten that doesn’t cause an Int64 to overflow when. The function subtracts startdate from enddate. Using DbFunctions, accessed via EF. Sql Server 2016 and later have a DATEDIFF_BIG function that can be used to get the milliseconds. It can be used to do date math as well. DATEADD(date_part, value, input_date) date_part -- the part of date to which the value will be added (values listed below). month, day, quarter, year etc. The suggested syntax is: SELECT DATETIME_DIFF (DATETIME "2010-07-07 10:20:00",DATETIME "2008-12-25 15:30:00", SECOND) which works ok. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact-SQL date and time data types and functions. Unfortunately T-SQL now has a DATEDIFF_BIG but not yet a DATEADD_BIG (or an option to accept BIGINT for the argument.